Posted By
Csabo
on 2024-10-20
18:44:06
|  Re: Interupt timers - actual time represented
Maybe I'm misunderstanding the question, but... The shortest instruction you can execute takes 2 cycles. During this, the timer ($FF00/$FF01) appears do count down by one.
In other words, if you were to constantly read from the low byte of the first timer (LDA$FF00), that takes 4 cycles to executes, and the values you would be reading would be decrementing by 2.
Is this what you're asking? |
