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Posted By

RobertB
on 2006-01-29
14:54:05
 Re: JiffyDos for the Plus/4 !?!

Date: Sun, 29 Jan 2006 18:51:28 GMT
From: Maurice Randall
Newsgroups: comp.sys.cbm
Subject: Re: JiffyDOS Plus4/C16

I'm trying to decide on how to set up the function key
definitions for the C16 and Plus/4 in the JiffyDOS kernal.
A little input from some existing users might help.

JiffyDOS adds function key definitions to the 64 and VIC-20.
The 128 already uses the function keys in BASIC, but JiffyDOS
changes the definitions of them.

On the 64 and VIC-20, you can disable the function keys with
the @F command. On the 128, the @F command restores the
standard definitions, it doesn't disable the function keys.
The C16 and Plus/4 will work like the 128, @F will restore
the standard definitions if you don't like the way JiffyDOS
programs them. Of course, a small BASIC program will code
them any way you like.

In all cases, a SYS command can restore the JiffyDOS keys.
In my opinion, Commodore goofed when they labelled the F keys
on the C16 and Plus/4. It confuses a regular 64/128 user with
the numbering scheme. For this discussion, I will just call
the keys 1,2,3, and 4 as they sit on the keyboard. This would
be the same as F1,F3,F5, and F7 on a 64.

My plan is to code the keys similar to the way JiffyDOS 64
does it so there is some consistency for existing JiffyDOS
users. The main difference will be with key 4 on both the
C16 and Plus/4 and key 1 on the Plus 4. Here's the layout:

C16:
1 @$ (to display the directory)
2 / (to load a file)
3 ^ (to load and run a file)
4 HELP
SHIFT-1 @D (to display a BASIC program)
SHIFT-2 @T (to display a text file)
SHIFT-3 [left arrow] (to save a program)
SHIFT-4 @ S" (to delete a file)

The only difference between the C16 and C64 is key 4. I'm
leaving that with the help command because the key is
labelled "HELP".

Plus/4:
The Plus/4 is very similar to the C16 layout except for
key 1 in its shifted position. Instead of having @T on
that key, it will function to start the 3 in 1 software.
So that key definition gets moved from the unshifted
position to the shifted position.

I've given this considerable thought and feel the above
is the most logical setup. Any thoughts are welcomed.

-Maurice



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