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| From: pzsolt (all posts)
Date: 2000-07-25
Subject: Re: Interrupts
|
Hi,
> Read-modify-write instructions write the unmodified value back first. So,
> the ASL $ff09 will first write $82, then $04.
This is very interesting. ASL $xxxx is a 6 cycles long instruction. How do the instuctions work? What happen exactly in the cycles?
Is there any recipe for the instruction execution?
Greetings,
Zsolt
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